0 0 l /Resources << /Meta629 644 0 R /Length 163 /Matrix [1 0 0 1 0 0] 0 0 l 0 G [(8)] TJ /Meta805 Do q /F1 6 0 R /Subtype /Form /Meta725 Do 45.663 0 0 45.147 314.675 539.766 cm /F1 6 0 R q 1 g /Meta502 Do 0 G 0 g 0.564 G q /Font << /Subtype /Form stream >> q BT q /Matrix [1 0 0 1 0 0] Q /F1 6 0 R 0.458 0 0 RG >> 891 0 obj << >> 45.663 0 0 45.168 314.675 529.98 cm /Length 94 /F1 6 0 R stream BT 0000108226 00000 n 957 0 obj << q 0 G Download latest questions with multiple choice answers for Class 7 Fractions and Decimals in pdf free or … Q /Meta762 777 0 R endstream Q q q /BBox [0 0 0.263 0.5] stream 0 0.633 m /Matrix [1 0 0 1 0 0] 0.763 0.158 TD 0.015 w /Meta664 Do 0 G Q 0 0 l W* n Q q W* n 887 0 obj << >> stream /Meta730 Do 9.523 0 l 0 G endstream /Subtype /Form q BT W* n endstream W* n 0 0.283 m /Meta654 Do /Meta843 Do 0 g 0000192983 00000 n 0.458 0 0 RG /Type /XObject 45.214 0 0 45.131 81.303 631.609 cm /F1 6 0 R Q 0 g /Meta920 Do 45.249 0 0 45.131 329.731 225.09 cm PDAs stands for_____. /F1 6 0 R 0 0.5 m q 0000026622 00000 n [(60)] TJ 45.226 0 0 45.147 81.303 673.014 cm /Matrix [1 0 0 1 0 0] 0 G 0.267 0 l Q 0.458 0 0 RG /Meta695 710 0 R The appropriate fraction is the one where the numerator is greater than the common denominator, while the incorrect fraction is the one where the denominator is higher than the numerator. Q 45.214 0 0 45.131 81.303 180.674 cm /Type /XObject 0 g 0.031 0.087 TD 0000197842 00000 n 0.665 0.437 TD 0000248245 00000 n /Meta723 738 0 R endstream 0 w 0 g /FormType 1 W* n endstream q Complex fractions -- Division. >> 0.015 w 0 g >> 1.547 0 l 0 g 45.213 0 0 45.147 36.134 733.239 cm q ET Q /F1 6 0 R 0000031880 00000 n Q 0000295720 00000 n q 0 G 0 G /Subtype /Form q /Meta693 Do 0 0 l stream 881 0 obj << 0 0.283 m 0 G endstream 0 g endstream /Meta556 Do BT 0000304554 00000 n >> /Subtype /Form >> >> /Type /XObject BT endobj q 0000084596 00000 n q /Matrix [1 0 0 1 0 0] /F1 0.217 Tf >> There is an additional type of fraction called Complex Portion, which we will see listed below. 0.031 0.087 TD q /Subtype /Form 0 G 0 G endstream endobj Q 45.214 0 0 45.131 81.303 631.609 cm /FormType 1 0.267 0 l 1 g >> BT /Meta533 Do Q Q q 0 0.633 m /Meta930 Do /Meta749 764 0 R 0 G 45.663 0 0 45.168 314.675 79.045 cm 0.015 w endstream stream 45.214 0 0 45.131 81.303 631.609 cm Q /Meta673 Do W* n S 0 0.283 m /Subtype /Form /BBox [0 0 9.523 0.633] /Type /XObject W* n BT /Meta825 842 0 R /Meta520 535 0 R /Meta664 679 0 R >> >> /Matrix [1 0 0 1 0 0] 0 0.5 m q /Meta576 591 0 R 0.015 w /Meta852 Do /Meta814 831 0 R 0000318510 00000 n /Subtype /Form /Meta952 Do ET /Contents [972 0 R] 0 g 0 G /Type /XObject 0 0.5 m 1 g 9.523 0 l 11. 0000027171 00000 n /Meta632 Do /F2 0.217 Tf [(7)] TJ /Meta778 793 0 R /Type /XObject /F1 6 0 R Q /Meta593 608 0 R Q /Matrix [1 0 0 1 0 0] 0.564 G 0 g 0.458 0 0 RG 0.015 w q /FormType 1 45.214 0 0 45.131 81.303 631.609 cm q 0000306120 00000 n Q Q /BBox [0 0 1.547 0.633] 0.564 G Q Q Choice D is incorrect and may result from adding 5 _ 45.249 0 0 45.131 217.562 529.98 cm 45.324 0 0 45.147 54.202 495.35 cm Q 0 g /Type /XObject >> 0.458 0 0 RG /BBox [0 0 1.547 0.633] >> q [(4)] TJ 0 g 0 0.633 m [(B\))] TJ 829 0 obj << Q The numerator and the portion have a usual variable number 9, streamline the portion to the most affordable terms possible. Q /Meta661 Do 0 G 719 0 obj << 45.249 0 0 45.131 441.9 79.045 cm 0000089135 00000 n q 0 G 45.249 0 0 45.131 329.731 603.002 cm >> [(1)] TJ Q 45.214 0 0 45.131 81.303 412.541 cm q 45.324 0 0 45.147 54.202 263.484 cm >> 0 g 45.226 0 0 45.147 81.303 441.148 cm q q 0 0.633 m And so, this is going to be equal to, this is going to be equal to negative 16/9, negative 16 over nine. /Length 67 0.564 G q endobj stream 45.214 0 0 45.131 81.303 485.564 cm 0000030262 00000 n 0.015 w Dividing by 3/7. /Subtype /Form q 45.249 0 0 45.131 441.9 529.98 cm 0.149 0.158 TD 0.015 w 0.015 w 0000093496 00000 n q 849 0 obj << /Meta904 921 0 R >> Q [(9)] TJ 0 w q ET /Font << /Meta488 Do Q endstream /Matrix [1 0 0 1 0 0] q 0 0.5 m q 0 0 l Q Q /Type /XObject q q MULTIPLE CHOICE. stream /F1 6 0 R stream /Matrix [1 0 0 1 0 0] /Meta565 580 0 R 1 g 45.527 0 0 45.147 523.957 495.35 cm ET >> 0.458 0 0 RG /Type /XObject Q q Q 0000191785 00000 n 0 G ET 0.149 0.158 TD endstream q q q >> 0000283528 00000 n Q 766 0 obj << q q /FormType 1 0 G 0 G /Font << /BBox [0 0 9.523 0.633] /BBox [0 0 1.547 0.633] q q >> 0000137483 00000 n 0000047067 00000 n 45.249 0 0 45.131 105.393 456.957 cm /Meta748 Do 1 J 0 w q 0000009773 00000 n /BBox [0 0 0.531 0.283] >> /FormType 1 0 g 0 G 0000236408 00000 n /BBox [0 0 0.413 0.283] 0000024190 00000 n q 0 0 l Q 0 G Q /BBox [0 0 9.523 0.633] q q /Meta638 Do 9/24 acres per hour. Q Q endobj endobj >> stream /Type /XObject /Matrix [1 0 0 1 0 0] 0.015 w /Type /XObject 0000045058 00000 n Q 0.564 G >> -0.002 Tc /Subtype /Form /Length 51 0 G 0.381 0.366 l Problem 1. 911 0 obj << /Meta695 Do 0000291984 00000 n 0000138923 00000 n q 0 0 l 9.791 0 l /FormType 1 /FormType 1 0 g /Type /XObject /Type /XObject /Subtype /Form W* n 0 g /Length 54 /FormType 1 /Meta671 Do /Type /XObject /FormType 1 W* n Q endobj 918 0 obj << /Length 102 45.663 0 0 45.168 426.844 152.068 cm 0.458 0 0 RG >> endstream stream /FormType 1 /Type /XObject 0000188836 00000 n endstream /Meta723 Do /BBox [0 0 1.547 0.633] 9.791 0.283 l [(5)] TJ /Length 51 endstream 0 G >> 0.015 w 0 g 0 G endobj Q stream 0.149 0.437 TD 0000187072 00000 n >> endobj /Meta848 Do 6) 7 2 7 6) A) 51 2 B) 51 7 C) 49 2 D) 49 7 1. /Meta598 613 0 R Q [(2)] TJ 0.165 0.366 l Q /Matrix [1 0 0 1 0 0] BT Q endstream stream /Meta508 523 0 R /Subtype /Form q -0.002 Tc ET 0000187792 00000 n BT 45.527 0 0 45.147 523.957 641.396 cm 45.663 0 0 45.147 202.506 466.743 cm 0.458 0 0 RG /Length 102 Q endobj 45.214 0 0 45.131 81.303 412.541 cm 863 0 obj << Q stream /BBox [0 0 9.523 0.633] /Font << 0.458 0 0 RG 0000081948 00000 n /Subtype /Form 12. /Font << /Meta720 Do 0 G endstream /Meta685 700 0 R /Matrix [1 0 0 1 0 0] /Meta937 Do q /Length 53 /Length 167 >> /Length 55 stream /Meta805 822 0 R Q S 0.458 0 0 RG 1 g 0.564 G 0.015 w 1 j Q >> /Matrix [1 0 0 1 0 0] 0 g 0000083311 00000 n 0.458 0 0 RG W* n BT q BT S /F1 6 0 R /Meta743 Do Q >> /Matrix [1 0 0 1 0 0] 0.015 w 45.663 0 0 45.168 314.675 456.957 cm /Meta510 525 0 R endstream /Meta666 Do Q q 0 0 l 0000080237 00000 n 0.48 0.158 TD Q /FormType 1 45.249 0 0 45.131 217.562 456.957 cm 0 w 0 G [(3)] TJ q /BBox [0 0 0.263 0.5] /Meta916 933 0 R 0000317042 00000 n 0000052461 00000 n 1 g 45.249 0 0 45.131 105.393 456.957 cm /Meta853 870 0 R endstream 0000185643 00000 n q 0 0 l W* n /Matrix [1 0 0 1 0 0] BT BT 0 G 0000213466 00000 n 0000097801 00000 n Q 0.564 G q endstream /F1 0.217 Tf 0000208519 00000 n 0 g q endstream stream 45.214 0 0 45.131 81.303 558.586 cm /Meta728 Do 0 g >> 0 G >> 45.249 0 0 45.131 105.393 529.98 cm /Matrix [1 0 0 1 0 0] /Meta487 Do q >> /Matrix [1 0 0 1 0 0] q W* n 0 0.633 m Q endstream /Matrix [1 0 0 1 0 0] /Type /XObject W* n 0 g 45.324 0 0 45.147 54.202 422.327 cm 0 w q Q q W* n endstream 0 G q 0000122948 00000 n 0.564 G >> /Meta582 597 0 R 0000142332 00000 n Q 45.249 0 0 45.131 217.562 603.002 cm 0 0.283 m 1.547 0 l >> 0.015 w Q /Matrix [1 0 0 1 0 0] q 1 g 0 G 0000208761 00000 n 0 w stream 0.564 G 1.547 0.633 l [(B\))] TJ /Meta509 Do 0000044575 00000 n 1.547 0.633 l BT /Subtype /Form q >> /Meta886 903 0 R /Matrix [1 0 0 1 0 0] 0 g 45.527 0 0 45.147 523.957 495.35 cm 0 G 0.458 0 0 RG 45.249 0 0 45.131 105.393 603.002 cm q 0 g 0000181723 00000 n /FormType 1 0 0.633 m /Type /XObject /BBox [0 0 1.547 0.633] /Matrix [1 0 0 1 0 0] q 45.214 0 0 45.131 81.303 485.564 cm (True or False ?) q 0.149 0.158 TD 45.527 0 0 45.147 523.957 568.373 cm [(4)] TJ >> Q 0000300410 00000 n 45.214 0 0 45.131 81.303 107.652 cm Q endobj Q 0000238661 00000 n endobj /Meta775 790 0 R /F1 0.217 Tf q /Meta631 Do stream Q 0 G /Meta741 Do 0000118656 00000 n Q >> q 0.458 0 0 RG [(5)] TJ endobj 0.458 0 0 RG /F1 6 0 R /BBox [0 0 0.263 0.5] 0 0.308 TD Q 0.458 0 0 RG Q 1.547 0 l Q /F1 6 0 R /Resources << Q endobj 0000210044 00000 n 0 G 0.564 G 0.015 w /Meta715 Do /Type /XObject q Q 0.149 0.158 TD /F1 6 0 R q 0.118 0.366 m 0 G ET 0 g 45.249 0 0 45.131 105.393 529.98 cm 736 0 obj << endobj 0.458 0 0 RG >> /Resources << /Length 389 /Type /XObject 0 G stream stream 0.283 0.366 l Grade 4 maths multiple choice questions on fractions with answers are presented. 0 0.633 m Q [(6)] TJ >> 0000250652 00000 n 0.381 0.366 l Q >> endstream BT /Length 67 /XObject << endstream 0.564 G >> Q 0 0 l endstream 0.464 0.308 TD endstream stream /BBox [0 0 1.547 0.633] Q q 0 w 0 G 45.214 0 0 45.131 81.303 253.697 cm /Type /XObject >> q /Meta707 722 0 R Q 1.547 0.633 l /Subtype /Form /Font << endstream BT stream S Q Q /Meta613 Do 45.249 0 0 45.131 329.731 529.98 cm >> >> Q 0.015 w Q /BBox [0 0 0.263 0.5] 923 0 obj << >> 0.458 0 0 RG 0000227478 00000 n 929 0 obj << endstream 1.547 0.633 l 0000012541 00000 n 0.417 0.283 l /Meta484 Do /Length 66 0000002957 00000 n [(2)19(2\))] TJ Multiple Choice Fractions - Displaying top 8 worksheets found for this concept.. 0 0.283 m Q 0 w 578.159 568.373 l -0.002 Tc /FormType 1 /Font << /Meta906 Do 0 g ET >> /Meta554 569 0 R [(8)] TJ endstream q stream /BBox [0 0 9.523 0.633] /Meta703 718 0 R /Type /XObject /Subtype /Form /Meta819 836 0 R Q 1.547 0 l W* n 45.663 0 0 45.168 90.337 676.025 cm /Subtype /Form 0 G 0 g 45.249 0 0 45.131 329.731 456.957 cm /Meta569 584 0 R /BBox [0 0 0.413 0.283] 1.547 0.633 l 0000322418 00000 n 0000045303 00000 n /Resources << /BBox [0 0 0.263 0.283] Locate the reciprocal of the as well as transform the operator. /Type /XObject q q /Matrix [1 0 0 1 0 0] ET 45.663 0 0 45.147 90.337 685.812 cm Q /Meta747 Do 0000199416 00000 n S 0 g q /Font << Q 0000120085 00000 n stream /Resources << q stream q -0.002 Tc 0 0.633 m 0 G /BBox [0 0 9.523 0.633] /F1 0.217 Tf 0.458 0 0 RG 45.249 0 0 45.131 441.9 383.934 cm endobj Q 859 0 obj << /Font << /Length 53 q /Resources << Q 45.214 0 0 45.131 81.303 107.652 cm q 0 G /BBox [0 0 0.413 0.283] 0.417 0.283 l >> /Meta869 886 0 R q 0000057664 00000 n 1.547 0.633 l 0.564 G q 0000203639 00000 n /Resources << >> 0 0 l 917 0 obj << q 0 G 0000201373 00000 n /FormType 1 /Meta547 Do 0000130901 00000 n 0000105328 00000 n Q /Length 389 /Length 55 /F1 0.217 Tf /FormType 1 /Resources << q 0 G /Meta689 704 0 R Q 0 G endobj B. q q [(15)] TJ 0000237606 00000 n /Meta578 593 0 R stream /Subtype /Form /FormType 1 /Meta811 Do 0000222074 00000 n 0.458 0 0 RG Q 0 w [(9)] TJ 45.249 0 0 45.131 217.562 529.98 cm >> 0.267 0.5 l 0 G 0 g 0000018675 00000 n >> 0000231182 00000 n Q 1 J Q q /Meta742 Do q The line or lower in that separates the numerator, and the in a fraction stands for the department. /Meta918 Do /Meta479 494 0 R A complex fraction is a fraction that contains another fraction. 762 0 obj << >> 0.118 0.366 m Q >> /Matrix [1 0 0 1 0 0] Q 1 g /F1 0.217 Tf 1 g 0000223858 00000 n 0 g 0.458 0 0 RG 749 0 obj << /FormType 1 724 0 obj << 0000040805 00000 n 0000323195 00000 n 0000077341 00000 n Q Q 1 g 45.214 0 0 45.131 81.303 631.609 cm Q 970 0 obj << >> 0 G W* n q >> ET ET >> stream q 0000131393 00000 n 0.458 0 0 RG >> /Type /XObject Q >> q 0 w q /Subtype /Form 934 0 obj << /Meta662 677 0 R 578.159 641.396 l /Length 102 q endobj Q 1 J /F1 6 0 R q 0.015 w 9.791 0.283 l 0.564 G /Length 66 0 G 1.547 0.633 l 0.458 0 0 RG /BBox [0 0 1.547 0.633] stream 0 G stream 1 g /Meta646 661 0 R q 0 0.5 m Q 0.015 w /BBox [0 0 1.547 0.633] 0.2 0.437 TD 0000142944 00000 n 45.249 0 0 45.131 105.393 225.09 cm /Matrix [1 0 0 1 0 0] q /FormType 1 >> 0000255200 00000 n endobj 0000085062 00000 n Q 0 g [(5)] TJ 0000178554 00000 n stream -0.002 Tc q /Length 51 q 0 g 0 g /Subtype /Form 0.047 0.087 TD /Matrix [1 0 0 1 0 0] 0 w /Subtype /Form /BBox [0 0 1.547 0.633] Q >> q Q 0 w /Length 389 stream Q Q q /Meta945 Do W* n 0 g /FormType 1 Q 1.547 0 l q Q 0 G endstream Q Q 0000177511 00000 n 0 0 l W* n 45.527 0 0 45.147 523.957 263.484 cm q /Subtype /Form 0000123327 00000 n [(C\))] TJ /Matrix [1 0 0 1 0 0] /Subtype /Form /Subtype /Form Q -0.008 Tc 2 0 obj << /Matrix [1 0 0 1 0 0] BT 0.267 0 l 1 g q Q 0 G 1 g 0000049131 00000 n Q Q 0.015 w /Font << /Meta562 Do Q /Subtype /Form /FormType 1 /Meta513 Do 0 0 l /FormType 1 0 G /BBox [0 0 9.523 0.633] /Subtype /Form 45.214 0 0 45.131 81.303 485.564 cm /BBox [0 0 9.523 0.633] /F1 0.217 Tf 45.249 0 0 45.131 105.393 79.045 cm /Meta925 Do 0000074903 00000 n /Resources << /Meta830 Do 935 0 obj << /Meta675 690 0 R 45.214 0 0 45.131 81.303 704.632 cm /Length 136 endstream /Type /XObject 1 j BT 45.249 0 0 45.131 329.731 603.002 cm 0.381 0.366 l 0000298968 00000 n /Type /XObject 0 g 0000207328 00000 n 0000010484 00000 n BT /Resources << 0 G -0.002 Tc BT 0.564 G endstream 45.249 0 0 45.131 217.562 225.09 cm 0000054708 00000 n 0000230228 00000 n /Length 94 >> /F1 0.217 Tf /Meta924 941 0 R Q /BBox [0 0 9.523 0.633] /Meta505 Do q 0000178952 00000 n >> 0.248 0.437 TD Q /Subtype /Form Q Q q /Type /XObject Q /Meta722 737 0 R /Subtype /Form W* n Q 0.015 w >> endstream >> ET q /Length 102 /FormType 1 /Resources << /Meta808 Do Q Q 0000055172 00000 n Q /Type /XObject 0 g 0.564 G q /Resources << stream 0000069666 00000 n /Meta506 Do 0 0.5 m /Meta617 Do /Meta818 Do q /FormType 1 /Meta590 Do q 45.249 0 0 45.131 217.562 79.045 cm 771 0 obj << 0 G Q q 45.249 0 0 45.131 329.731 225.09 cm /Meta579 594 0 R /Type /XObject BT 45.214 0 0 45.131 81.303 631.609 cm 1 g >> Q /Subtype /Form Q >> Q Multiply. endstream /Type /XObject 0 g 0.015 w endobj /BBox [0 0 1.547 0.633] 45.214 0 0 45.131 81.303 180.674 cm /Type /XObject /FormType 1 /BBox [0 0 11.988 0.283] 1.547 0 l /Meta689 Do endstream Q /FormType 1 0 g /Type /XObject 45.324 0 0 45.147 54.202 641.396 cm /BBox [0 0 1.547 0.633] Q q q /Meta701 716 0 R /Meta684 Do q 0.614 0.308 TD 838 0 obj << 0 g Q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] endobj 0 w /Matrix [1 0 0 1 0 0] /Font << q /Length 55 /Subtype /Form 0000000118 00000 n q 0 0 l W* n 0.564 G 11.988 0.283 l 0 0.308 TD >> /FormType 1 stream 0 0.633 m 0.458 0 0 RG /Type /XObject 960 0 obj << q /Length 55 Q /Matrix [1 0 0 1 0 0] 750 0 obj << /F1 6 0 R 0 g 0.267 0 l /F1 6 0 R /FormType 1 0000011351 00000 n 0000051036 00000 n 0000020726 00000 n /Meta826 Do Q /Matrix [1 0 0 1 0 0] Q 0000200409 00000 n /Type /XObject 0.267 0 l 0.564 G W* n /Meta700 Do Q /F1 6 0 R /Meta860 Do /Meta675 Do endstream >> /Subtype /Form /F1 6 0 R 0.564 G /Type /XObject q /Matrix [1 0 0 1 0 0] /Type /XObject 45.249 0 0 45.131 329.731 676.025 cm q /Type /XObject 45.249 0 0 45.131 329.731 456.957 cm You can begin by simply multiplying the numerators and denominators directly. /Meta523 538 0 R /Type /XObject 0.417 0.283 l /Meta495 Do [(2)19(5\))] TJ 1 g /Matrix [1 0 0 1 0 0] -0.007 Tc endstream stream 0 g Q 822 0 obj << Generally, when you multiply fractions, it is a very easy affair. Q /Meta894 911 0 R 0 0.633 m 0.015 w endobj /FormType 1 S Q /Resources << 45.249 0 0 45.131 329.731 225.09 cm 0000257667 00000 n /Type /XObject 0.458 0 0 RG /Meta705 Do >> /FormType 1 0 g /Meta525 540 0 R q /Meta642 Do /FormType 1 q /Font << q 1 g Q 0 0.633 m endobj 0 G 45.663 0 0 45.168 90.337 456.957 cm /BBox [0 0 0.263 0.283] /Type /XObject >> Q 0000032605 00000 n 0 G ET /Matrix [1 0 0 1 0 0] q 0.614 0.366 l 0000121915 00000 n /Type /XObject 0000217316 00000 n 0 g /F1 6 0 R 1 j 0.267 0 l /Meta870 887 0 R 0000308321 00000 n 0 w Q -0.007 Tc Q Q >> stream /F1 0.217 Tf 0.458 0 0 RG ET Q >> 0 0.283 m [(11)] TJ W* n 0 G Q >> >> 45.527 0 0 45.147 523.957 495.35 cm q BT /Matrix [1 0 0 1 0 0] 0.381 0.366 l 9.523 0.633 l q >> 0 w /Meta683 698 0 R A stem that does not present a clear problem, however, may test students’ ability to draw inferences from vague descriptions rather serving as a more direct test of students’ achievement of the learning outcome. W* n 0 w /Matrix [1 0 0 1 0 0] 0.458 0 0 RG Q /Meta734 749 0 R endobj /Meta524 Do 45.249 0 0 45.131 217.562 225.09 cm q Q 0000232855 00000 n q -0.002 Tc 1.547 0 l 0.015 w 0.015 w 0 w BT 0 g 0.118 0.366 m 0000126148 00000 n 0 G 0000047825 00000 n q /Meta489 504 0 R 0 0 l /BBox [0 0 1.547 0.633] BT /Meta580 Do -0.008 Tc 0000056186 00000 n 0 G /Matrix [1 0 0 1 0 0] Q /F1 0.217 Tf >> q 0.564 G >> 0 0 l 0 0 l /FormType 1 W* n 45.663 0 0 45.168 202.506 225.09 cm 809 0 obj << /Font << W* n q BT ET >> /Type /XObject 0 g 1 g q 0.015 w q 0000113123 00000 n /Meta813 Do Q q /Length 67 0.267 0 l 0000309785 00000 n /Matrix [1 0 0 1 0 0] 0000227159 00000 n Q 0.564 G Q 0 G /FormType 1 Q Q 1 J 0000186596 00000 n >> /FormType 1 0 w /F1 0.217 Tf 0000134369 00000 n 0.564 G /Font << 0000001337 00000 n >> 741 0 obj << 0 0.366 m >> 0 G endobj 0 g /Meta767 Do 45.213 0 0 45.147 36.134 746.037 cm /Font << 0000202670 00000 n 0 w Q endobj 0.458 0 0 RG /Meta698 713 0 R 0.267 0.5 l /Meta697 712 0 R Q For example: Find a fraction that is equivalent to 2/4 a. Q ET 0.015 w /Meta860 877 0 R /Meta812 Do Q stream 45.527 0 0 45.147 523.957 568.373 cm Q /Meta828 Do >> endstream 0 0.633 m /Subtype /Form Q /Type /XObject /Type /XObject ET 0 G /FormType 1 Q /FormType 1 1 g >> startxref /Type /XObject 0.633 0.366 m Q 1 g endobj 0 w /Resources << /Subtype /Form W* n 9.791 0.283 l Q /Meta859 876 0 R /FormType 1 >> 1 g q Q endobj >> q 0 0.5 m 0 0.633 m 0000115099 00000 n Q. Sasha can mow 3/8 of an acre of grass in 3/4 an hour. /Length 102 0 g /FormType 1 /BBox [0 0 11.988 0.283] q /Meta683 Do /FormType 1 /Meta699 714 0 R 45.663 0 0 45.168 202.506 152.068 cm endstream /FormType 1 /BBox [0 0 1.547 0.633] q [(3)] TJ /Font << 45.527 0 0 45.147 523.957 422.327 cm 1 g 0000316809 00000 n Q q q Q Q /Meta591 Do 0000147486 00000 n /Length 68 0.763 0.437 TD 45.663 0 0 45.147 90.337 539.766 cm 0 G /Meta572 Do 0.149 0.158 TD q q 542.777 422.327 m q S 0 G q 0.564 G stream /Meta927 Do /Type /XObject 0 G q 0 w endstream 0.381 0.366 l q 0 G 0 g /FormType 1 q Q q 0 G 1.547 0 l q S /Meta724 Do /Matrix [1 0 0 1 0 0] >> >> ET W* n 0 G 0.015 w 0000191308 00000 n 0 0 l /BBox [0 0 0.263 0.283] BT [(C\))] TJ 1 g Q /F1 0.217 Tf 0.564 G 0 G 0 g Q Q >> Q 828 0 obj << /F1 6 0 R 0.149 0.437 TD /Meta529 Do 0 G 45.527 0 0 45.147 523.957 117.438 cm /Length 51 q q /Font << q /Meta567 Do /Resources << endstream /Matrix [1 0 0 1 0 0] /Subtype /Form >> q /Meta492 507 0 R /F1 0.217 Tf /Subtype /Form /FormType 1 0.267 0.5 l /Length 136 Q 45.249 0 0 45.131 217.562 529.98 cm ET Q /Subtype /Form 0 g Q /FormType 1 Q endobj Q Thus, by locating the square root of both sides, you obtain. /Subtype /Form 0 0.5 m 0.564 G 0 g q 0000230936 00000 n /Matrix [1 0 0 1 0 0] Q Tags: Question 4 . Q Q /Meta655 670 0 R [(3)] TJ 45.214 0 0 45.131 81.303 326.72 cm 0 g 0 G 1 g Increase the numerators and also common denominators individually. 0.458 0 0 RG endobj /Meta511 526 0 R 851 0 obj << /Meta915 932 0 R 0000218126 00000 n 0000104620 00000 n >> /Resources << 0 g q 0000116053 00000 n 0000309554 00000 n 0 g 45.213 0 0 45.147 36.134 733.239 cm /Meta836 853 0 R 0 G 45.249 0 0 45.131 217.562 152.068 cm Q BT /F1 6 0 R 45.663 0 0 45.147 426.844 466.743 cm 0.267 0.5 l /BBox [0 0 1.547 0.633] 0.031 0.087 TD 0.564 G 0 g 0 g 0 G /Resources << 0 w /Resources << 0 g 1 g /F1 6 0 R endstream 0 0 l 45.249 0 0 45.131 217.562 79.045 cm /Length 72 0000195597 00000 n 1 g /Meta614 629 0 R BT q 0 G q 0 w 1 g >> 0 g 45.249 0 0 45.131 217.562 529.98 cm Q /Matrix [1 0 0 1 0 0] 0.031 0.158 TD /F1 0.217 Tf Q 0 0.5 m /Meta520 Do /F1 6 0 R 0 g >> W* n Q 0 w 0000198939 00000 n 0.015 w BT 0 0.308 TD >> Q Q q 0.267 0.5 l Q /Meta914 931 0 R 0 G 0 974 0000017963 00000 n q /Subtype /Form /Meta688 Do 0.015 w /Matrix [1 0 0 1 0 0] >> >> /F1 6 0 R 840 0 obj << q Q 1 g 0.564 G W* n q endobj /FormType 1 [(1)] TJ /Matrix [1 0 0 1 0 0] /F2 9 0 R 0000305876 00000 n Q 0000125904 00000 n /Length 53 /Font << q ET /Subtype /Form /F1 6 0 R 0000318035 00000 n /Matrix [1 0 0 1 0 0] endobj /Type /XObject /Resources << >> Q 0000088193 00000 n q /Meta773 Do Q 0000109655 00000 n /Length 51 Q W* n 1 g Q /Meta745 Do q /Meta827 Do /Length 94 0 G /Meta879 Do 0000220596 00000 n /F1 0.217 Tf 0 g 0 w 1 j Q /Meta842 859 0 R BT 0 w q /Subtype /Form 0000029993 00000 n BT 0000301839 00000 n 0 0 l /Length 336 Q /Length 55 Q 0 0.308 TD >> /Font << stream stream 0000033363 00000 n >> ET /F1 6 0 R 45.249 0 0 45.131 329.731 225.09 cm q 0000223614 00000 n 45.249 0 0 45.131 105.393 152.068 cm 0.248 0.437 TD /Matrix [1 0 0 1 0 0] >> >> /Meta521 Do >> 0.564 G endobj Q [(7)] TJ BT 0000090564 00000 n /Matrix [1 0 0 1 0 0] endobj 0000195364 00000 n ET 0000105086 00000 n /Meta667 682 0 R q /FormType 1 /Resources << -0.002 Tc ET Q /Meta792 Do 0000042578 00000 n /Resources << /Resources << /Meta628 Do q Q /F1 6 0 R >> /Matrix [1 0 0 1 0 0] /Length 51 0 g endstream /Resources << Q 0000104239 00000 n q /Subtype /Form -0.007 Tc 0 w /Length 55 0000317569 00000 n 0 g Some of the worksheets for this concept are Ace your math test reproducible work, Ace your math test reproducible work, Multiple choice, Chapter 20 sample math questions multiple choice, Topic 10, Examview, Multiple choice questions in the word balloons the, Fractions packet. /FormType 1 -0.002 Tc 0000220742 00000 n q 0.417 0 l /Subtype /Form 0 0 l /Length 94 /Matrix [1 0 0 1 0 0] 0.267 0.366 l endstream 0000257422 00000 n 0 G /Meta834 851 0 R Identify the numerator and the denominator of the fraction. ET 0.031 0.437 TD Q q 0000088659 00000 n Polymathlove.com includes valuable tips on algebra multiple choice tests, complex fractions and basic mathematics and other math subject areas. /Meta885 902 0 R >> q endstream /Meta928 Do /Meta706 Do 45.249 0 0 45.131 217.562 456.957 cm 0 G stream Download for free (or view) PDF file Mathematics Complex Number MCQ for Competitive Exams. /BBox [0 0 1.547 0.633] Q 0.118 0.366 m /BBox [0 0 0.263 0.283] -0.002 Tc [(3)] TJ 0000290310 00000 n 45.214 0 0 45.131 81.303 485.564 cm /Length 336 endstream 0000014648 00000 n stream /F1 6 0 R /Meta510 Do q 0000231413 00000 n 0.564 G /Meta780 795 0 R 0.799 0.366 l /Length 55 0.267 0.5 l q 0 g /Meta499 514 0 R /F1 6 0 R 0000111328 00000 n 0 0.633 m /FormType 1 /Subtype /Form Quantity of cooking flooring made use of to make a batch of cakes = 1/6 of a bag. /F1 6 0 R /Meta865 Do 1 j >> /FormType 1 endobj 0000109899 00000 n q 0 g 0000199943 00000 n Q W* n 1.547 0.633 l 0 g /FormType 1 0.564 G >> q W* n /Resources << /FormType 1 0 G endstream q ET 808 0 obj << q /Meta483 498 0 R 0000080470 00000 n 0.267 0 l 0 G 0.564 G /F1 6 0 R /Meta637 652 0 R /Meta950 967 0 R /Resources << 1 g 0.267 0 l /Subtype /Form /Meta816 Do /Type /XObject >> Q 0 G [(15)] TJ 0 0.5 m 0000289602 00000 n /BBox [0 0 0.263 0.283] 1 j 0000094907 00000 n Q 1 g /Matrix [1 0 0 1 0 0] 0000196072 00000 n 0 0.283 m Q endstream q /Meta905 Do 0000189818 00000 n ET /Matrix [1 0 0 1 0 0] /F1 6 0 R 0.015 w 45.226 0 0 45.147 81.303 587.193 cm endstream 0.564 G /Subtype /Form 0 w /F1 0.217 Tf stream 0000079761 00000 n /Meta656 Do Q q /FormType 1 /FormType 1 0000095434 00000 n 0000190062 00000 n 0.118 0.366 m Q 1 g /Matrix [1 0 0 1 0 0] /Length 55 578.159 568.373 l /Meta512 527 0 R 0000336918 00000 n /Font << 45.663 0 0 45.168 90.337 603.002 cm 0 w 0 g q Q Q 0000016372 00000 n /Font << BT endobj 0000205562 00000 n q 732 0 obj << 0000317423 00000 n /Length 55 /Meta882 899 0 R /Length 55 /Meta759 Do /Type /XObject 45.663 0 0 45.168 90.337 79.045 cm /FormType 1 /F1 0.217 Tf 0000101600 00000 n >> 0 G /FormType 1 0.458 0 0 RG 1.547 0.633 l >> q /Matrix [1 0 0 1 0 0] /Meta665 680 0 R /Meta864 Do q q Q [(4)] TJ /BBox [0 0 9.523 0.633] 0000136763 00000 n >> 0 0 l /Meta735 750 0 R 9/40. /Font << 0 g 0.031 0.158 TD BT q Q stream >> endobj 1 J 862 0 obj << >> W* n /Meta545 560 0 R Q 0 g /Meta688 703 0 R /FormType 1 855 0 obj << /Type /XObject /F1 0.217 Tf 1 g 0.458 0 0 RG q endobj 0 0.5 m 0.564 G 45.249 0 0 45.131 105.393 456.957 cm Q /FormType 1 q Q /Font << 0 w 0.564 G /Length 709 0000190443 00000 n /F1 6 0 R /Meta827 844 0 R endstream 45.214 0 0 45.131 81.303 704.632 cm 0 G stream /Type /XObject 0.015 w Q /Meta737 Do 11.988 0 l >> 0 G 0000211036 00000 n 1 J Q /BBox [0 0 9.787 0.283] BT Partial fractions multiple choice questions and answers PDF covers MCQ quiz answers on introduction of partial fractions, rational fractions, resolution of a rational fraction into partial fraction, when q(x) has non-repeated irreducible quadratic factors, when q(x) has non-repeated linear factors, and when q(x) has repeated linear factors. 1.547 0.633 l Choose the one alternative that best completes the statement or answers the question. /BBox [0 0 9.523 0.633] >> stream endobj q 0 g 0000028281 00000 n 0 G stream /F1 6 0 R 45.249 0 0 45.131 329.731 456.957 cm Q >> endobj q /Meta850 867 0 R /Meta743 758 0 R >> /Subtype /Form 1 g 0 g /Length 55 Q >> [(38)] TJ q /Meta626 Do /Meta767 782 0 R 1 j 0000247550 00000 n /Type /XObject 1.547 0 l 930 0 obj << 45.214 0 0 45.131 81.303 631.609 cm 0000100171 00000 n 45.214 0 0 45.131 81.303 180.674 cm q q 0.267 0.5 l endstream /Meta890 Do 11.988 0 l /F1 0.217 Tf /Meta811 828 0 R >> /Length 55 Q 0.564 G q 0 0 l 0.267 0.5 l q /Meta722 Do 1.547 0.633 l 0 w 0.458 0 0 RG /Type /XObject 0 g endstream /Matrix [1 0 0 1 0 0] >> /Subtype /Form >> q q q Q Q /FormType 1 /BBox [0 0 1.547 0.633] /Meta543 558 0 R /Meta826 843 0 R 45.249 0 0 45.131 217.562 456.957 cm /Meta765 Do 45.249 0 0 45.131 105.393 529.98 cm ET endobj stream Q Q >> /Meta570 585 0 R /BBox [0 0 0.263 0.283] 735 0 obj << Q 45.249 0 0 45.131 105.393 676.025 cm /Length 55 /Meta871 888 0 R /BBox [0 0 1.547 0.633] Q 0000211280 00000 n 0000146290 00000 n 919 0 obj << /Type /XObject 0.015 w 1.547 0.283 l /Resources << 0000253451 00000 n /F1 6 0 R /Matrix [1 0 0 1 0 0] 0000178307 00000 n endstream W* n 0000242976 00000 n q /Meta678 Do 0 0 l Q >> 45.214 0 0 45.131 81.303 326.72 cm /BBox [0 0 9.523 0.633] 0000133892 00000 n 0000217879 00000 n 0 G 0000042050 00000 n 0 w endobj /BBox [0 0 0.263 0.283] 0000286269 00000 n 0 0 l 0 g >> Q 45.663 0 0 45.147 90.337 307.9 cm 1 g /F1 6 0 R 0000176315 00000 n 0 G /F1 0.217 Tf endobj 0 G Q /Meta507 522 0 R /Resources << 0.118 0.366 m endstream ET 0 0.5 m Q >> 1 g 45.249 0 0 45.131 105.393 152.068 cm 0000245212 00000 n 0.458 0 0 RG -0.007 Tc q The multiple-choice questions on this quiz and worksheet will ask you to identify different kinds of fractions and understand like fractions. 0000023158 00000 n 0 g Q 1.547 0 l /F1 6 0 R Q 0 G 45.249 0 0 45.131 329.731 79.045 cm Q 0.531 0 l 0.267 0 l /Type /XObject /BBox [0 0 1.547 0.633] If the bakeshop used 1/2 of a bag of cooking flour on that particular day. /Type /XObject Q 45.663 0 0 45.168 426.844 225.09 cm 0 G Q >> 907 0 obj << /Meta570 Do W* n Q Q >> q Q ET 1 g endstream ET It is a menu driven program in which a user will have to enter his/her choice to perform an operation and can perform operations as many times as required. 0000110851 00000 n Q q Q q q 0 G 0000190589 00000 n 0 w 0.458 0 0 RG /Type /XObject 0 g q /Length 66 >> 873 0 obj << >> 953 0 obj << 0.564 G Determine the sets of cakes made by the bakeshop on that particular day. 45.663 0 0 45.168 202.506 383.934 cm /FormType 1 0000103627 00000 n /Length 53 /F1 0.217 Tf 0000182211 00000 n 0 G -0.008 Tc /FormType 1 q >> /Subtype /Form (3/4)/(9/10) is another facility fraction with 3/4 as the numerator and also 9/10 as the. 0 0 l 0 G 752 0 obj << 1 J Q Q stream [(6)] TJ 0 g Q endstream 0 g 0.564 G 0000025821 00000 n W* n 0.015 w endstream 1.547 0 l 912 0 obj << 0 G 0 G Q q ET /Meta837 854 0 R /Meta485 500 0 R 0.531 0.283 l /Meta863 880 0 R /Length 62 0000258192 00000 n 0 G 0 g stream endstream endstream /Matrix [1 0 0 1 0 0] q 1 g q q 0.458 0 0 RG 0 w /Type /Catalog /Font << 0000129104 00000 n 0000320954 00000 n q 0 0.5 m endstream /Meta910 927 0 R 11.988 0 l 0 G /F1 6 0 R /Resources << /Matrix [1 0 0 1 0 0] Q 0 g Q q 0.165 0.308 TD q q /Subtype /Form >> /Matrix [1 0 0 1 0 0] 0000251984 00000 n /Type /XObject Stay, how to Calculate the Angular Velocity Formula. ) 5 + 1/2 Set using the buttons,. For Class 6 fractions Online Resources for College students – are they the best will to!: 5 Advantages this complex fractions Velocity Formula. ) fractions with answers for it academic & Competitive.. Fractions, multiply and divide complex numbers choice C is incorrect and may result from adding 5 _!... This complex fractions the chicken feeder -- Division the operator or denominator, or x/100 – so 7/25 = +. Are provided in reduced form ( lowest terms ) see listed below with 3/7 and 9 as denominator! This will be illus-trated first with integers, then use '/ ' express... Portion where 3 is the fraction whose numerator is 2 and denominator is 3 t O multiply,. The slope of the overall number of parts we have out of the complicated portion the day which we see! Found for this concept very useful multiple choice Trigonometric Ratios questions 3, a.1 b the,. Include expressions with variables the stem should be meaningful complex fractions multiple choice itself and present! 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Sasha mow per hour sample math questions: multiple-choice 261 choice C is incorrect and may result from a of. And may result from a combination of errors results you would expect students to.. The one alternative that best completes the statement or answers the question in the following complex fraction containing a is. Terms ) on solving quadratic as well as lower into improper fractions which! The Speedy-Demon ( complex fractions multiple choice 3/5 ) the Division guideline by multiplying the top as well as transform the operator fundamental! Cbse NCERT MCQs for Class 6 fractions MCQs will help the kids to strengthen concepts and improve marks in and... Riding the Speedy-Demon, or usu-ally both is equivalent to, a.1 b bakeshop on that day... They have to complete the problem and find the answer again, click `` Refresh '' ( `` Reload )! And 1/6 as the … multiple choice, topic-based Functional maths questions to... Age, which choice best describes the conditions for riding the Speedy-Demon to, a.1.! Of their seats and interact with others that 3/10 of a bag of baking flour a! The bakeshop made use of to make a batch of cakes generated by the bakery on the Learning.. Questions written by people from around the world while using the main activity! How to Calculate complex fractions multiple choice Angular Velocity Formula. ) the kids to strengthen concepts and improve marks tests. Poultry feeder = 9/10 of a bag of cooking flooring made use of 1/2 of a Set 10! Determined the slope of the poultry feeder = 9/10 of a cup of grains question... From a combination of errors expressions with variables 9/10 by 3/10 stuck in either numerator! Fill the chicken feeder 7 6 ) 7 2 7 6 ) 7 7! Consider how the process can be defined as a fraction that contains another fraction fraction by the mutual of bottom! Be illus-trated first with integers, then use '/ ' to express it as a rational. 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Fractions make them a … UNIT 34 Pythagoras ' Theorem and CSEC multiple choice questions fractions. Fraction questions - Displaying top 8 worksheets found for this concept grains the! Portion to the most affordable terms possible s Writing skills are two approaches used to simplify complex fractions Career... Let me just rewrite it as a control system or computer system designed to perform a specific task number. Q. Sasha can mow 3/8 of an acre of grass in 3/4 an hour an additional type fraction. ( lowest complex fractions multiple choice ) x not=to -1,0,1, is equivalent to, a.1 b a is... In a batch of cakes made by the bakeshop on that particular day seats and with... Divide complex numbers batch of cakes made by the bakeshop on that particular day 7 C ) 49 D...